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Question

A=2^i+^j,B=3^i^k and C=6^i2^k.
Value of A2B+3C would be

A
20^i+5^j+4^k
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B
20^i5^j4^k
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C
4^i+5^j+20^k
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D
5^i+4^j+10^k
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Solution

The correct option is C 20^i5^j4^k
A2B+3C=(2^i+^j)2(3^j^k)+3(6^i2^k)

=2^i+^j6^j+2^k+18^i6^k=20^i5^j4^k

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