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B
→a
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C
[→a→b→d]→b
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D
[→a→b→d]→c
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Solution
The correct option is C[→a→b→d]→c Let us take ¯¯¯aׯ¯b as ¯¯¯x The question becomes ¯¯¯x×[¯¯cׯ¯¯d]+[¯¯¯a¯¯b¯¯c]¯¯¯d =(¯¯¯x.¯¯¯d)¯¯c−(¯¯¯x.¯¯c)¯¯¯d+[¯¯¯a¯¯b¯¯c]¯¯¯d =[¯¯¯a¯¯b¯¯¯d]¯¯c−[¯¯¯a¯¯b¯¯c]¯¯¯d+[¯¯¯a¯¯b¯¯c]¯¯¯d =[¯¯¯a¯¯b¯¯¯d]¯¯c