Question

Velocity of a particle is given by $v=3-t$ m/s. The distance traveled by particle in 1st four second is

• A. $2m$
• B. $3m$
• C. $4m$
• D. $5m$

Answer 1

Answer: (C)

$4m$

{C} $V=3-t,m/s$

Integrate to get displacement

${\int }_0^{4}3-t\cdot dt\Rightarrow 3t-\frac{t^2}{2}{\int }_0^4\Rightarrow 12-8=4m$