velocity of a particle moving on x axis is v = x^2 + x. find acceleration when x = 2

Open in App

Solution

Suggest Corrections

Similar questions

Q. The velocity of a particle moving on the x-axis is given by

v = x^{2} + x

where v in m/s and x is in m. Its acceleration in

m / s^{2}

when passing through the point x=2m.

Q. Velocity in

m / s

of a particle moving along

x -

axis varies with time as

v = (10 + 5 t - t^{2})

. At time

t = 0, x = 0.

Acceleration of particle at

t = 2 s

x m / s^{2}

, then value of

x

The velocity of a moving particle along the x-axis is given as $v = x^{2} - 5 x + 4 (i n m/s),$ where x denotes the $x - c o o r d i n a t e$ of the particle in meters. Find the magnitude of the acceleration of the particle when the velocity of the particle is zero?

Q. A particle is moving on the

x

-axis. The velocity of the particle increases with

x

v = v_{0} + k x

. Which of the following is true about the acceleration of the particle?

Q. A particle moves along the X-axis with velocity

v = \frac{d x}{d t} = f (x)

then the acceleration of the particle is?

Join BYJU'S Learning Program