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Question

Velocity of the electron in electron microscope is 1.6×106m/sec. What would be the wavelength of the electron?

A
5.39A
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B
4.55A
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C
3.54A
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D
6.78A
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Solution

The correct option is B 4.55A
λ=hmν... de- Broglie concept
λ=hm×1.6×106λ=4.55×1010m
=4.55A°

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