Question

Velocity-time graph of a particle moving in a straight line is shown in the figure. Find the total displacement of the particle.

• A. 40 m
• B. 60 m
• C. 80 m
• D. 100 m

Answer 1

The correct option is C 80 m

Displacement= Area under velocity-time graph

Hence, $s_{OA}=\frac{1}{2}\times 2\times 10=10m$

$s_{AB}=2\times 10=20m$

or $s_{OAB}=10+20=30m$
$s_{BC}=\frac{1}{2}\times 2(10+20)=30m$

or $s_{OABC}=30+30=60m$

and $s_{OABCD}=60+20=80m$