1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Velocity versus displacement graph of a particle moving in a straight line is as shown in figure. The acceleration of the particle is:

A
Increases linearly with x
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Constant
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Increases parabolically with x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A Increases linearly with x From the graph, velocity-displacement equation can be written as: v=vo+αx…(1) Here, vo and α are positive constants. Differentiating Eq. (1) with respect to x we get, dvdx=α=constant Acceleration of the particle can be written as a=dvdt Or, a=vdvdx a=(vo+αx)α=v0α+α2x Above equation signifies linear relationship of a and x. Thus, acceleration increases linearly with x.

Suggest Corrections
2
Join BYJU'S Learning Program
Related Videos
Motion Under Variable Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program