Velocity - time $(v - t)$ graph for a moving objects is shown in the figure. Total displacement of the object during the time intervals when there is non-zero acceleration, is

60 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

30 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $50 m$
Between time interval $20 s$ to $40 s$ , there is non-zero acceleration and retardation. Hence, distance travelled during this interval.
$=$ Area between time interval $20 s$ to $40 s$
$= \frac{1}{2} \times 20 \times 3 + 20 \times 1 = 30 + 20 = 50 m$ .

Suggest Corrections

Similar questions

Q. Velocity time (v - t) graph of a moving object is shown in the figure. Total displacement of the object during the time interval when there is non-zero acceleration and retardation is

Q. A velocity-time graph for a moving object is shown below. What would be the total displacement during time t =0 to t = 6s?

Q. The graph between the displacement (S) and time (t) for a particle moving in a straight line is shown in figure. During the intervals OA, AB, BC and CD, the acceleration of the particle is.

Q. An object changes its velocity from 30ms

^{- 1}

to 40ms

^{- 1}

in a time interval of 2 seconds. What is its acceleration?

The velocity-time graph of a particle moving in a straight line is as shown in figure, initial velocity of particle is zero. Find the total displacement of the particle during its journey.

Join BYJU'S Learning Program

Velocity - time (v−t) graph for a moving objects is shown in the figure. Total displacement of the object during the time intervals when there is non-zero acceleration, is

The correct option is C 50 mBetween time interval 20 s to 40 s, there is non-zero acceleration and retardation. Hence, distance travelled during this interval.= Area between time interval 20 s to 40 s=12×20×3+20×1=30+20=50 m.

Velocity - time $(v - t)$ graph for a moving objects is shown in the figure. Total displacement of the object during the time intervals when there is non-zero acceleration, is

The correct option is C $50 m$
Between time interval $20 s$ to $40 s$ , there is non-zero acceleration and retardation. Hence, distance travelled during this interval.
$=$ Area between time interval $20 s$ to $40 s$
$= \frac{1}{2} \times 20 \times 3 + 20 \times 1 = 30 + 20 = 50 m$ .