Verify that $a \div (b + c) \neq (a \div b) + (a \div c)$ for each of the following values of a, b and c.
a = 12, b = - 4, c = 2

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Solution

$a = 12, b = - 4, c = 2$
$a \div (b + c) = 12 \div (- 4 + 2) = 12 \div (- 2) = - 6 (a \div b) + (a \div c) = [12 \div (- 4)] + [12 \div 2] = - 3 + 6 = 3 H e n c e, a \div (b + c) \neq (a \div b) + (a \div c)$

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a \div (b + c) \neq (a \div b) + (a \div c)

Verify that a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c) for each of the following values of a, b and c.

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Question 2(a)
Verify that $a \div (b + c) \neq (a \div b) + (a \div c)$ for each of the following values of a, b and c.
a = 12, b = - 4, c = 2

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Question 2(b)
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