Question

Verify that
(i) 4 is a zero of the polynomial, p(x) = x - 4.
(ii) -3 is a zero of the polynomial, q (x) = x + 3.
(iii) $\frac{2}{5}$ is a zero of the polynomial, $f\left(x\right)=2-5x$
(iv) $\frac{-1}{2}$ is a zero of the polynomial, g(y) = 2y + 1.

Answer 1

(i) $p\left(x\right)=x-4\Rightarrow p\left(4\right)=4-4=0$

Hence, 4 is the zero of the given polynomial.

(ii) $q\left(x\right)=x+3\Rightarrow q(-3)=-3+3\Rightarrow q(-3)=0$

Hence, 3 is the zero of the given polynomial.

(iii) $f\left(x\right)=2-5x\Rightarrow f\left(\frac{2}{5}\right)=2-5\times \frac{2}{5}=2-2=0$

Hence, $\frac{2}{5}$ is the zero of the given polynomial.

(iv) $g\left(y\right)=2y+1\Rightarrow g\left(\frac{-1}{2}\right)=2\times \left(\frac{-1}{2}\right)+1=-1+1=0$

Hence, $\frac{-1}{2}$ is the zero of the given polynomial.