Question

Verify whether the following are zeroes of the polynomial, indicated against them.
(i) p(x) = 3x + 1, x = $-\frac{1}{3}$
(ii) $p\left(x\right)=5x-\pi ,x=\frac{4}{5}$
(iii) $p\left(x\right)=x^2-1,x=1,-1$
(iv) p(x) = (x +1) (x -2), x = - 1, 2

Answer 1

(i) Yes, $-\frac{1}{3}$ is the zero of the polynomial.
3x + 1 = 0, for $x=-\frac{1}{3}.$

(ii) No, it is not the zero of the given pilynomial.
$5x-\pi =5\times \frac{4}{5}-\pi =4-\pi \ne 0$

(iii) Yes, it is the zero of the polynomial.
$x^2-1=1^2-1=0forx=1and{x}^2-1=(-1{)}^2-1=0forx=1$

(iv) Yes, it is the zero of the polynomial.
$(x+1)(x-2)=0forx=-1,orx=2$