CameraIcon

SearchIcon

MyQuestionIcon

2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

(a-b)^2 Expansion and Visualisation

Question 89 v...

Question

Question 89 (vi)

Factorise the following, using the identity, $a^{2} + 2 a b + b^{2} = (a + b)^{2}$

$a^{2} x^{2} + 2 a x + 1$

Open in App

Solution

We have, $a^{2} x^{2} + 2 a x + 1$
$= (a x)^{2} + 2. a x .1 + (1)^{2} = (a x + 1)^{2} = (a x + 1) (a x + 1)$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Question 89 (viii)

Factorise the following, using the identity,

a^{2} + 2 a b + b^{2} = (a + b)^{2}

a^{2} x^{2} + 2 a b x y + b^{2} y^{2}

Q. Question 90 (vi)

Factorise the following, using the identity,

a^{2} - 2 a b + b^{2} = (a - b)^{2}

p^{2} . y^{2} - 2 p y + 1

Question 92 (vi)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$9 x^{2} - 1$

Q. Question 89 (v)

Factorise the following, using the identity,

a^{2} + 2 a b + b^{2} = (a + b)^{2}

4 x^{2} + 4 x + 1

Q. Question 89 (xi)

Factorise the following, using the identity,

a^{2} + 2 a b + b^{2} = (a + b)^{2}

9 x^{2} + 24 x + 16

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

(a-b)^2 Expansion and Visualisation

Standard VII Mathematics

Join BYJU'S Learning Program

CrossIcon