Question 90 (vii)

Factorise the following, using the identity, $a^{2} - 2 a b + b^{2} = (a - b)^{2}$ .

$a^{2} y^{2} - 2 a b y + b^{2}$

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Solution

We have
$a^{2} y^{2} - 2 a b y + b^{2} = (a y)^{2} - 2. a y . b + b^{2} = (a y - b)^{2} = (a y - b) (a y - b)$

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