Vijay has to go to office from home. He travels the first half of the distance at speed of 30 km/hr. For the remaining distance he travels at 10 km/hr for half the time and at 20 km/hr for the rest. Find his average speed.
20 km/hr
Let's assume, time taken from A to B is t1, B to C is t2 and C to D is t2.
∴ Total distance = AB + BC + CD
= 30t1+10t2+20t2
Total time = t1+2t2
∴Average speed=30t1+10t2+20t2t1+2t2=30t1+30t2t1+2t2
But given, AB = BD = BC + CD
∴30t1=10t2+20t2
⇒30t1=30t2
⇒t1=t2
Average speed = 30t1+30t2t1+2t2=60t13t1 = 20 km/hr.