Vijay is pulling a block with 22 N force and Gopal is pulling it with 10 N force in opposite direction. Vijay is able to pull the block towards himself for a total distance of 6.5 m. Find the net work done.

12 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

90 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

85 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

78 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
78 J

$Work done = Net force \times total displacement = (22 - 10) \times 6.5 = 12 \times 6.5 = 78 J$

Suggest Corrections

Similar questions

Q. Vijay is pulling a block with 22 N force and Gopal is pulling it with 10 N force in opposite direction. Vijay is able to pull the block to a distance of 6.5 m. The net work done is

Vijay and Gopal are pulling a block with 22 N force 10 N force respectively in opposite direction. If Vijay pulls the block by a total distance of 6.5 m towards himself. Find the net work done by the forces acting on the block.

Q. Vijay is pulling a block with

22 N

force and Gopal is pulling it with

10 N

force in the opposite direction. The block moves a distance of

6.5 m

in the same direction in which Vijay is pulling it. The work done on the block is:

Vijay is pulling a block with 22 N force and Gopal is pulling it with 10 N force in opposite direction. Vijay is able to pull the block a total distance of 6.5 m. Find the net work done by the two forces.

Q. Vijay and Gopal are pulling a block with

24 N

force and

8 N

force respectively in the opposite directions. The displacement of the block towards Vijay is

6 m

. Find the net work done by the forces acting on the block.

Join BYJU'S Learning Program

Vijay is pulling a block with 22 N force and Gopal is pulling it with 10 N force in opposite direction. Vijay is able to pull the block towards himself for a total distance of 6.5 m. Find the net work done.

The correct option is D 78 J Work done=Net force×total displacement=(22−10)×6.5=12×6.5=78J

The correct option is D
78 J

$Work done = Net force \times total displacement = (22 - 10) \times 6.5 = 12 \times 6.5 = 78 J$