Question

Volume occupied by $4.4$ g of $C{O}_2$ is:

• A. 2240 lit at STP
• B. 2.24 lit at STP
• C. 22.4 lit at STP
• D. 224 lit at STP

Answer 1

Answer: (B)

2.24 lit at STP

The molecular mass of carbon dioxide is $44$ g/mol.

Thus, $4.4$ g of carbon dioxide corresponds to $\frac{4.4}{44}=0.1$ mole.

At STP, $1$ mole of a gas occupies $22.4$ L.

Thus, $0.1$ mole will occupy $2.24$ L.

Hence, option B is correct.