Volume of 0.1 M $H_{2} {S O}_{4}$ solution required to neutralize 40 ml of 0.1 M NaOH solution is :

40 m l

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39 m l

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20 m l

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10 m l

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Solution

The correct option is C $20 m l$
We know that :

$N_{1} V_{1} = N_{2} V_{2}$

$N o r m a l i t y = M o l a r i t y \times B a s i c i t y$

For sulphuric acid, the basicity is 2.

$∴ N_{1} = 0.1 \times 2 = 0.2 N$

$V_{1} = ?$

$N_{2} = 0.1 \times 1 = 0.1 N$

$V_{2} = 40 m l$

$0.2 \times V_{1} = 0.1 \times 40$

$V_{1} = 20 m l$
Therefore, the option is $C$ .

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