Question

Volume of $18.0M$ $H_{2}S{O}_4$ required to prepare $1.0$ L of a $0.9$ M solution of $H_{2}S{O}_4$ is :

• A. $50.0$ mL
• B. $10.0$ mL
• C. $500.0$ mL
• D. $5.0$ mL

Answer 1

The correct option is A $50.0$ mL

The expression for molarity is $M_1{V}_1=M_2{V}_2$.

Substituting values in the above expression, we get

$V_1=\frac{M_2{V}_2}{M_1}=\frac{1000\times 0.9}{18}=50.0$ mL

Hence, option $A$ is correct.