Volume of 4.4g of CO2 at STP is
2.24 litres
No. of moles of CO2=Given massmolar mass
=4.444=0.1moles
No. of moles = volume available22.4 litres
⇒0.1=volume available22.4 litres
⇒Volume=0.1×22.4=2.24
Given volume is the required volume here,
So the volume occupied by 4.4g of CO2 is 2.24 litres.