Volume of detonating gas at STP, produced in the decomposition of $1$ mole of water, by an electric current is:

22.4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

11.2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

33.6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

44.8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $33.6$ L
The reaction for the decomposition of water is $H_{2} O \to H_{2} + \frac{1}{2} O_{2}$ .
The mixture $H_{2} + \frac{1}{2} O_{2}$ is the detonating gas.
Thus, $1$ mole of water gives $1$ mole of hydrogen and half mole of oxygen.
One mole of any gas at STP occupies $22.4$ L.
Hence, the volume of detonating gas obtained on decomposition of one mole of water is $22.4 \times (1 + 0.5) = 33.6$ L.

Suggest Corrections

Similar questions

29 g

of butane is burnt in excess of

O_{2}

at STP. Find the volume of the

C O_{2}

gas produced at STP.

The vapour density of a gas is 11.2. The volume occupied by 11.2 g of the gas at ATP will be

Q. The volume of gases evolved when dil.

H_{2} S O_{4}

is electrolysed when 2F of charge is passed at STP is:

Q. If each O-atom has two equivalents, volume of one equivalent of

O_{2}

gas at STP is
(a) 22.4 L (b) 11.2 L
(c) 5.6 L (d) 44.8 L

$4.5 g$ of Aluminium is deposited at cathode from $A l^{3 +}$ solutions by a certain quantity of electric charge. The volume of hydrogen produced at STP from $H^{+}$ ions in solution by the same quantity of electric charge will be:

Join BYJU'S Learning Program

Volume of detonating gas at STP, produced in the decomposition of 1 mole of water, by an electric current is:

Volume of detonating gas at STP, produced in the decomposition of $1$ mole of water, by an electric current is: