Question

Volume strength of $1.5N{H}_2{O}_2$ is :

• A. 4.8
• B. 8.4
• C. 3.0
• D. 8.0

Answer 1

The correct option is B

8.4

Volume strength is defined as the term which is used to express the concentration of $H_2{O}_2$ in terms of volumes of oxygen gas based on its decomposition to form water and oxygen.
Decomposition reaction:
$H_2{O}_2\to 2H_{2}O+O_2$
Let us assume that the solution of M moles of $H_2{O}_2$ is present in 1L solution.
2 moles of $H_2{O}_2$ gives 1 mol of oxygen
we can also say that 2 moles of $H_2{O}_2$ produces 22.4L of oxygen gas at STP.
1 mole $H_2{O}_2$ will produce=$\frac{22.4L}{2}\times 1=11.2L$ of oxygen gas.
Hence, M mole of $H_2{O}_2$ will produce (11.2 x M) L of oxygen gas.
So, 1L of $H_2{O}_2$ will give (11.2 x M) L of oxygen gas.
therefore, the volume strength of $H_2{O}_2$ =11.2 x M
n factor of $H_2{O}_2$ is 2
we know that,
N=nM
normality of $H_2{O}_2$=1.5N
So, volume strength of $H_2{O}_2$= $11.2\times \frac{N}{2}=11.2\times \frac{1.5}{2}=8.4$