Walking at three-fourth of his normal speed a man is late by 2.5 hr. Then his usual time is :

7.5 hr

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3.5 hr

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3.25 hr

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8 hr

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Solution

The correct option is A 7.5 hr
New speed $= \frac{3}{4}$ of normal speed.
$∴$ New time taken $= \frac{4}{3}$ of normal time.
$\Rightarrow (\frac{4}{3}$ of normal time $) - ($ normal time $) = 2.5$ hr

$\Rightarrow \frac{1}{3}$ of normal time $= 2.5$ hr

$\Rightarrow$ of normal time $= 2.5 \times 3 = 7.5$ hr

Option A is correct.

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Walking at three-fourth of his normal speed a man is late by 2.5 hr. Then his usual time is :

The correct option is A 7.5 hrNew speed=34 of normal speed.∴ New time taken=43 of normal time.⇒(43 of normal time)−(normal time)=2.5hr⇒13 of normal time=2.5 hr⇒ of normal time=2.5×3=7.5 hrOption A is correct.