Water flows out through a circular pipe, whose internal radius is 1cm , at the rate of 80cm per sec. Into an empty cylindrical tank , whose radius is 40cm . By how much Will the water rise in the tank in half an hour??

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Solution

Radius of tank, r1 = 40 cm Internal radius of circular pipe, r2 = 1 cm Length of water-flow in 1 sec = 80 cm Length of water-flow in 30 mins, h2 = 80 x 60 x 30 = 1,44,000 cm Vol. of water in cyl. Tank = Vol. of water-flow from the circular pipe in half an hour (πr1^2) h1=(πr2^2) h2 40 x 40 x h1 = 1 x 1 x 1,44,000 h1 = 1,44,000/(40×40) = 90 cm Level of water in cyl. Tank rises in half-an-hour = 90 cm

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