Water is added in excess to a 100g sample labelled as 112%H2SO4 This solution is then treated with 5.3g of Na2CO3. the volume of CO2 evolved at 1atm and 300K after a complete reaction will be : H2SO4+Na2CO3→Na2SO4+H2O+CO2
A
2.46 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
24.60 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.27 L
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
12.30 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C 1.27 L 112%H2SO4 means water is in excess and the mass of H2SO4 112 g Reaction : H2SO4+Na2CO3→NaSO4+CO2+H2O number of mole of H2SO4=112/98 number of mole of Na2CO3=5.3/106=0.05 Na2CO3 is limiting reagent so 0.05 moles of CO2 produced at STP which volume is eqaul to 1.27 L