Question

Water is discharged from a pipe of cross- sectional area $3.2c{m}^2$ at the speed of $5$ m/s .Calculate the volume of water discharged in $c{m}^3$ per sec.

Answer 1

$\log 27=1.341$
$\therefore \log 3^3=1.341$ ....$\log a^b=b\log a$
$\therefore \log 3=0.447$
$\log 300=\log (3\cdot {10}^2)=\log 3+2=0.477+2=2.447$ ...$\log (a\cdot b)=\log a+\log b$