Question

Water rises in a vertical capillary tube upto a length of $10cm.$ If the tube is inclined at ${45}^o$, the length of water risen in the tube will be,

• A. $10cm$
• B. $10\sqrt{2}cm$
• C. $\frac{10}{\sqrt{2}}$
• D. none of these

Answer 1

The correct option is B $10\sqrt{2}cm$

The vertical rise in the level of liquid is constant.
Hence for an inclined tube, the effective length is $\frac{h}{\cos \theta }$
So, the length of water risen in the tube will be $10\sqrt{2}cm$