Question

Water rises to a height of $2\text{cm}$ in a capillary tube. If the tube is tilted ${60}^{\circ }$ from the vertical, water will rise in the tube to a length in cm: (answer upto 2 decimal places)

Answer 1

We know that the excess pressure inside the capillary tube is given by $\frac{2T}{R}$.
Since, water rises to height of $2\text{cm}$ in a capillary tube.

If tube is at ${60}^{\circ }$ in this case height must be equal to $h=2\text{cm}$.
$l=\frac{h}{\text{cos}\theta }=\frac{h}{\text{cos}{60}^{\circ }}$
$l=\frac{2\text{cm}}{\frac{1}{2}}$
$l=4\text{cm}$