Wavelength of light required to excite an electron in an hydrogen atom from level n=1 to n=2 will be:
(Given: Planck's constant (h)=6.62×10−34Js, speed of light (c)=3×108ms−1)
A
1.216×10−7 m
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B
2.816×10−7 m
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C
6.500×10−7 m
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D
8.500×10−7 m
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Solution
The correct option is A1.216×10−7 m E=−2.178×10−18(Z2n2)J
For hydrogen, Z=1
So, E1=−2.178×10−18(112)J E2=−2.178×10−18(122)J
Now, E2−E1=ΔE=2.178×10−18(112−122)=hcλ ⇒λ=1.216×10−7m