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Byju's Answer
Standard VIII
Physics
Static Friction
We can prove ...
Question
We can prove 1=2
proof: a=b
a square = ab
a sq -b sq = ab-b sq
(a-b)(a+b)=b(a-b)
a+b = b
b+b =b
2b=b
2=1
but fundamentally it is wrong
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Solution
proof: a=b
a square = ab
a sq -b sq = ab-b sq
(a-b)(a+b)=b(a-b)
we cannot cancel (a-b) from both sides , because its given a=b
Therefore we know that a-b=0
and we cannot cancel zeroes from lhs and rhs
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