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Electrolytic Refining of Copper

We have CuS...

Question

We have $C u S O_{4}$ solutions (blue) in two beakers A and B. In beaker A we add Ag pieces and in B we add Zn pieces. What will happen in B?

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Solution

As we know, Zn is more reactive than Cu so in second case Zn will react with $C u S O_{4}$ and $Z n + C u S O_{4} \to Z n S O_{4} + C u$

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