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Question

We have two solutions, one is 1 L of 0.1 M NaCl and the other is 2 L of 0.2 M CaCl2. Using only these two solutions, a solution of 2.5 L volume can be prepared which has [Cl]=0.34M. Calculate the osmotic pressure of the solution prepared.
Given: t=300K,(R=0.082 L atm mol1K1)

A
10.8 atm
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B
12.8 atm
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C
5.6 atm
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D
None of these
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Solution

The correct option is B 12.8 atm
The expression for the osmotic pressure is π=CRT

Here, C is the concentration. Its expression is

C=[Cl]+[Na+]+[Ca2+]=(0.34+0.1×0.52.5+0.2×22.5)=0.34+0.02+0.16=0.52
Note :

We have to use 500ml of NaCl soln and 2 L of CaCl2 solution.

Substitute values in the expression for the osmotic pressure.
π=0.52×0.082×300 atm=12.792 atm

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