We will get an angle of measure 22-5- by drawing angle bisector from -

To construct 22.5^∘, we have to bisect the angle between 0^∘ angle and 45^∘ angle. The resulting angle = 0^∘ + 45^∘/2 = 22.5^∘ nbsp; Hence, option 'b' is corr ...

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Standard VII

Mathematics

Angle Bisector

We will get a...

Question

We will get an angle of measure ${22.5}^{\circ}$ by drawing angle bisector from ________.

0^{\circ} a n d 90^{\circ}

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0^{\circ} a n d 45^{\circ}

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0^{\circ} a n d 60^{\circ}

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45^{\circ} a n d 90^{\circ}

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Solution

The correct option is B $0^{\circ} a n d 45^{\circ}$
To construct ${22.5}^{\circ}$ ,
we have to bisect the angle between $0^{\circ}$ angle and $45^{\circ}$ angle.
The resulting angle $= \frac{0^{\circ} + 45^{\circ}}{2} = {22.5}^{\circ}$
Hence, option 'b' is correct.

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We will get an angle of measure 22.5∘ by drawing angle bisector from ________.

The correct option is B 0∘ and 45∘To construct 22.5∘, we have to bisect the angle between 0∘ angle and 45∘ angle. The resulting angle =0∘+45∘2=22.5∘ Hence, option 'b' is correct.

We will get an angle of measure ${22.5}^{\circ}$ by drawing angle bisector from ________.

The correct option is B $0^{\circ} a n d 45^{\circ}$
To construct ${22.5}^{\circ}$ ,
we have to bisect the angle between $0^{\circ}$ angle and $45^{\circ}$ angle.
The resulting angle $= \frac{0^{\circ} + 45^{\circ}}{2} = {22.5}^{\circ}$
Hence, option 'b' is correct.