Question

Wedge is accelerated towards left shown in figure. $\theta ={30}^{\circ }$ and all surface are smooth. The acceleration of block w.r.t wedge is $(g=10m/s^2)$

• A. $3m/s^2$
• B. $5m/s^2$
• C. $6m/s^2$
• D. $10m/s^2$

Answer 1

The correct option is B $5m/s^2$


Net force on the block relateive to wedge is

$F_{net}=mgsin\theta –macos\theta$

$=mgsin\theta –m\times 2gtan\theta .cos\theta$

$ma=-mgsin\theta$

$\therefore a=gsin\theta$, upwards

$=10\times sin{30}^{\circ }=5m/s^2$ upwards