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RMS and KE Expressions

Weight of 2...

Question

Weight of $2 L$ of nitrogen at N.T.P. is:

25

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1.25

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2.33

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14.0

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Solution

The correct option is C $1.25$ g
NTP stands for Normal Temperature and Pressure at NTP
Temperature is 293 K
Pressure is 1 atm
$P V = n R T$
$n = R T / P V$
$n =$ $\frac{1 a t m \times 2 L}{0.08206 L a t m / m o l \times 293 K} = 0.083 m o l$
Weight of $N_{2} =$ No. of moles $\times$ molar mass of $N_{2}$
$= 0.083 \times 28 = 2.33$ g

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