At STP weight of $1 l i t r e$ of a gas is $3.16 g r a m s$ and weight of $1 l i t r e$ of Hydrogen is $0.09 g m$ . If molecular weight of Hydrogen is 2, molecular weight of the gas is

Q. Calculate the number of oxygen atoms in

0.2 m o l e

N a_{2} C O_{3} \cdot 10 H_{2} O

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Weight of oxygen in 32.2 g Na2SO4.10H2O is:

The correct option is B 22.4 gmMoles of the given compound = 32.2322=0.1 mol Each molecule contains 14 O atomsMoles of oxygen =14×0.1=1.4 moles Weight of oxygen= 1.4×16=22.4 g

Weight of oxygen in $32.2$ g $N a_{2} S O_{4}$ . $10 H_{2} O$ is:

The correct option is B 22.4 gm
Moles of the given compound = $\frac{32.2}{322} = 0.1 m o l$

Each molecule contains $14 O a t o m s$

Moles of oxygen $= 14 \times 0.1 = 1.4 m o l e s$
Weight of oxygen= $1.4 \times 16 = 22.4 g$