What amount of heat is required by 50 g of copper to increase its temperature by 10- C - specific heat of copper -420 J - kg - C A- 5- CB- 6- CC- 7- CD- 8- C

The correct option is A 5°C Given : Rise in temperature Δ T_c = 10^∘C Mass M_c= 50 g = 0.05 kg, specific heat C_c= 420 J/kg ^∘C Heat required = Δ Q Δ Q ...

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Standard IX

Physics

Specific Heat Capacity

What amount o...

Question

What amount of heat is required by $50 g$ of copper to increase its temperature by $10^{\circ} C$ ? specific heat of copper = $420 J / k g^{\circ} C)$

5°C

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6°C

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7°C

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8°C

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Solution

The correct option is A
5°C

Given : Rise in temperature $Δ T_{c} = 10^{\circ} C$

$M a s s M_{c} = 50 g = 0.05 k g, s p e c i f i c h e a t C_{c} = 420 J / k g^{\circ} C$

Heat required = $Δ Q$

$Δ Q$ = $M_{c} C_{c} Δ T_{c}$

$Δ Q = 0.05 \times 420 \times 10 = 210 J$

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Similar questions

$50 g$ of copper is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $10 g$ of water, the rise in its temperature is (specific heat of copper = $420 J / k g /^{\circ} C$ )

$50 g$ of copper is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $10 g$ of water, then what would be the rise in its temperature?
(specific heat of copper $= 420 J / k g /^{\circ} C$ , specific heat of water $= 4200 J / k g /^{\circ} C$ )

50 g

of copper is heated to increase its temperature by

10^{\circ} C

. If the same quantity of heat is given to

10 g

of water, then the rise in its temperature is (specific heat of copper

= 420 J / k g /^{\circ} C

)

50

gm of copper is heated to increase its temperature by

10^{\circ} C

. If the same quantity of heat is given to

10

gm of water, the rise in its temperature is (Specific heat of copper =

420 Joule - k g^{- 1}^{\circ} C^{- 1})

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What amount of heat is required by 50 g of copper to increase its temperature by 10∘C? specific heat of copper = 420 J/kg ∘C)

The correct option is A 5°C Given : Rise in temperature ΔTc=10∘C Mass Mc=50 g=0.05 kg, specific heat Cc=420 J/kg ∘C Heat required = ΔQ ΔQ = McCcΔTc ΔQ=0.05×420×10=210 J

What amount of heat is required by $50 g$ of copper to increase its temperature by $10^{\circ} C$ ? specific heat of copper = $420 J / k g^{\circ} C)$

The correct option is A
5°C

Given : Rise in temperature $Δ T_{c} = 10^{\circ} C$

$M a s s M_{c} = 50 g = 0.05 k g, s p e c i f i c h e a t C_{c} = 420 J / k g^{\circ} C$

Heat required = $Δ Q$

$Δ Q$ = $M_{c} C_{c} Δ T_{c}$

$Δ Q = 0.05 \times 420 \times 10 = 210 J$