What are hybridisation states of each carbon atom in the following compounds?

$C H_{2} = C = O$

$C H_{3} C H = C H_{2}$

$(C H_{3})_{2} C O$

$C H_{2} = C H C N$ ,

$C_{6} H_{6}$

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Solution

$1 C H_{2} = 2 C = O$
C–1 is $s p^{2}$ hybridised.
C–2 is sp hybridised.

$1 C H_{3} 2 C H = 3 C H_{2}$
C–1 is $s p^{3}$ hybridised.
C–2 is $s p^{2}$ hybridised.
C–3 is $s p^{2}$ hybridised.

$C 1 H_{3} - O | | C 2 - C 3 H_{3}$
C–1 and C–3 are $s p^{3}$ hybridised.
C–2 is $s p^{2}$ hybridised.

$1 C H_{2} - 2 C H - 3 C \equiv N$
C–1 and C–2 are $s p^{3}$ hybridised.
C–3 is $s p$ hybridised.

$C_{6} H_{6}$
All the 6 carbon atoms in benzene are $s p^{2}$ hybridised.

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Similar questions

C H_{2} = C = O, C H_{3} C H = C H_{2}, (C H_{3})_{2} C O, C H_{2} = C H C N, C_{6} H_{6}

C H_{2} = C = O, C H_{3} C H = C H_{2}, (C H_{3})_{2} C O, C H_{2} = C H C N, C_{6} H_{6}

What are the hybridization states of each carbon atom(s) in the following molecules ?

(i) $C H_{3} * C H_{2} C H_{2} C H_{3}$

(ii) $C H_{2} = C^{*} H - C H = C H_{2}$

(iii) $C H_{3} * C H = C H - C H_{3}$

(iv) $H - * C \equiv C - H$

C H_{2} = C = O

C H_{3} i - O | | C i i - C H_{2} i i i - C N i v

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