Question

What are the $6$ trigonometric ratios ?

Answer 1

Define trigonometric ratios.

Let $\mathrm{A}$ be any specific angle of a right triangle, the $6$ trigonometric ratios are :

1. $\sin \left(\mathrm{A}\right)=\frac{\mathrm{Opposite}\mathrm{side}\mathrm{of}\mathrm{A}}{\mathrm{Hypotenuse}}$
2. $\cos \left(\mathrm{A}\right)=\frac{\mathrm{Adjacent}\mathrm{side}\mathrm{of}\mathrm{A}}{\mathrm{Hypotenuse}}$
3. $\tan \left(\mathrm{A}\right)=\frac{\mathrm{Opposite}\mathrm{side}\mathrm{of}\mathrm{A}}{\mathrm{Adjacent}\mathrm{side}\mathrm{of}\mathrm{A}}$
4. $\cot \left(\mathrm{A}\right)=\frac{\mathrm{Adjacent}\mathrm{side}\mathrm{of}\mathrm{A}}{\mathrm{Opposite}\mathrm{side}\mathrm{of}\mathrm{A}}$
5. $\sec \left(\mathrm{A}\right)=\frac{\mathrm{Hypotenuse}}{\mathrm{Adjacent}\mathrm{side}\mathrm{of}\mathrm{A}}$
6. $\csc \left(\mathrm{A}\right)=\frac{\mathrm{Hypotenuse}}{\mathrm{Opposite}\mathrm{side}\mathrm{of}\mathrm{A}}$