Construction of
ΔABC, given the perimeter (AB + BC + CA) = 'a' cm,
∠B=x∘ and
∠C=y∘.
Steps of construction:
Step 1: Draw the line segment XY = 'a' cm
Step 2: Draw the ray XL at X making an angle of
x∘ with XY
Step 3: Draw the ray YM at Y making an angle of
y∘ with XY
Step 4: Draw angle bisector of
∠LXY.
Step 5: Draw angle bisector of
∠MYX such that it intersects the angle bisector of
∠LXY at a point A.
Step 6: Draw the perpendicular bisector of AX such that it intersects XY at a point B.
Step 7: Draw the perpendicular bisector of AY such that it intersects XY at a point C.
Step 8: Join AB and AC
Thus, ABC is the required triangle.