what are the formulas to calculate specific heat and latent heat?

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Solution

$S p e c i f i c h e a t i s t h e q u a n t i t y o f h e a t r e q u i r e d t o r a i s e t h e 1 g r a m o f a n y s u b \tan c e b y 1 d e g r e e c e l s i u s . C = \frac{∆ Q}{m ∆ T} C = s p e c i f i c h e a t ∆ Q = h e a t g a i n e d o r l o s t m = m a s s o f t h e s u b s \tan c e ∆ T = C h a n g e i n t e m p e r a t u r e L a t e n t h e a t i s t h e h e a t r e q u i r e d f o r c h a n g e i n p h a s e . L = \frac{Q}{m} L = l a t e n t h e a t Q = a m o u n t o f h e a t m = m a s s o f t h e s u b s \tan c e$

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Similar questions

(a) Which property of water enables it to modify the climate?

(b) The density of water varies with temperature. What are its consequences?

(c) State the melting point, boiling point, specific heat capacity, specific latent heat of fusion and specific latent heat of vaporization of water.

3 k g

a t - 12^{\circ} C

100^{\circ}

= 2100 \times 10^{5} J {k g}^{- 1} K^{- 1}

= 4186 \times 10^{3} J {k g}^{- 1} K^{- 1}

c e = 3.35 \times 10^{5} J {k g}^{- 1}

= 2.256 \times 10^{6} J {k g}^{- 1}

1 k g

- 10^{o} C

100^{o} C

7, 77, 000 J

= 2100 J k g^{- 1} K^{- 1}

= 4200 J k g^{- 1} K^{- 1}

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