What are the voltage drops across each of the resistors in the circuit pictured below?

R_{1} \to 10 V; R_{2} \to 4 V; R_{3} \to 2 V; R_{4} \to 4 V

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R_{1} \to 1 V; R_{2} \to 3 V; R_{3} \to 2 V; R_{4} \to 4 V

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R_{1} \to 10 V; R_{2} \to 2 V; R_{3} \to 4 V; R_{4} \to 4 V

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R_{1} \to 1 V; R_{2} \to 4 V; R_{3} \to 4 V; R_{4} \to 2 V

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Solution

The correct option is A $R_{1} \to 10 V; R_{2} \to 4 V; R_{3} \to 2 V; R_{4} \to 4 V$
Given : Voltage of the battery $V = 20.0$ volts
Total resistance of the circuit $R_{T} = 5.0 + 2.0 + 1.0 + 2.0 = 10.0$ $Ω$
Current flowing through the circuit $I = \frac{20.0}{10.0} = 2.0$ A

Thus voltage drop across $R_{1}$ , $V_{1} = I R_{1} = 2.0 \times 5.0 = 10.0$ volts

Voltage drop across $R_{2}$ , $V_{1} = I R_{2} = 2.0 \times 2.0 = 4.0$ volts

Voltage drop across $R_{3}$ , $V_{3} = I R_{3} = 2.0 \times 1.0 = 2.0$ volts

Voltage drop across $R_{4}$ , $V_{4} = I R_{4} = 2.0 \times 2.0 = 4.0$ volts

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