Question

What change in volume results if 60.0 $mL$ of gas is cooled from 33${}^{0}C$ to 5.0${}^{0}C$?

Answer 1

$V_1/T_1=V_2/T_2$

(60.0 $mL$) / (306.0 $K$) = ($x$) / (278.00 $K$); $x$ = 54.50 $mL$