What do you observe when ethylene is passed through alkaline $K M n O_{4}$ solution ?

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Solution

When ethylene is passed through alkaline $K M n O_{4}$ solution 1, 2-Ethanediol is formed.
The Purple colour of $K M n O_{4}$ decolorizes.

$C H_{2} = C H_{2} + H - O - H + [O] Cold alkaline K M n O_{4} solution - ----------------- \to C H_{2} (O H) - C H_{2} (O H)$

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