Ethylene decolorizes alkaline ${K M n O}_{4}$ solution. This is due to:

monohydroxy compound

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dihydroxy compound

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carbonyl compound

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trihydroxy compound

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Solution

The correct option is A dihydroxy compound
Ethylene reacts with alkaline ${K M n O}_{4}$ solution and glycol (ethane-1,2-diol) forms as a product.
In this reaction pink color of ${K M n O}_{4}$ disappears.
The reaction can be given as follow:
$C H_{2} = C H_{2} + H_{2} O + [O] \to C H_{2} O H - C H_{2} O H$

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