Ethylene on reaction with alkaline $K M n O_{4}$ gives:

glycerol

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acetic acid

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glycol

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ethyl alcohol

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Solution

The correct option is B glycol
Ethylene on reaction with alkaline $K M n O_{4}$ gives ethylene glycol.
$H_{2} C = C H_{2} Ethylene + H_{2} O + [O] from K M n O_{4} \to H O - C H_{2} - C H_{2} - O H ethylene glycol$

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