Question

What does the following program print?
#include < stdio.h>
void f(int *p, int *q)
{
p = q;
*p = 2;
}
int i = 0, j = 1;
int main( )
{
f(&i, &j);
printf ("%d %d\n", i, j);
return 0;
}

• A. 2 2
• B. 0 1
• C. 0 2
• D. 2 1

Answer 1

The correct option is C 0 2

In the given program it begin from main function,
i and j are globally initialized by 0 and 1. So when we call function f(& i, & j) the address of i and j are passed.
when p = 1 and *p = 2 means
*q = 2. so value of *q is passed.
and value of *q return to j.
Value of i and j are 0 and 2 respected.
So printf("%d %d," i, j) gives output (0, 2)