Question

What happens in the following reaction?
${NH}_4^{+}+H_{2}O\leftrightharpoons {NH}_3+H_3{O}^{+}$

• A. Electron transfer
• B. Neutralization
• C. Double replacement
• D. Reduction
• E. Proton transfer

Answer 1

The correct option is E Proton transfer

$N{H}_4^{+}+H_{2}O\leftrightarrow N{H}_3+H_3{O}^{+}$
In this reaction the $H^{+}$ from the $N{H}_4^{+}$ is released because the $N{H}_4^{+}$ is Lewis acid, and $H_{2}O$ due to having lone pair of electrons, it act as base and accepts the proton.