What happens when:
(i) Formaldehyde is heated with $N H_{3}$
(ii) Acetone react with Bleaching Powder.
(iii) Formaldehyde reacts with Fehling Solution.

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Solution

(i) Formaldehyde is heated with $N H_{3}$ to obtain urotropine (hexamethylene tetramine).
$6 H C H O + 4 N H_{3} \to (C H_{2})_{6} N_{4} + 6 H_{2} O$
(ii) Acetone react with Bleaching Powder ( $C a O C l_{2}$ ) to form trichloroacetone. Hydrolysis of trichloroacetone gives chloroform.
$C a O C l_{2} + H_{2} O \to C a (O H)_{2} + C l_{2}$
$C H_{3} C O C H_{3} + 3 C l_{2} \to C C l_{3} C O C H_{3} + 3 H C l$
$2 C C l_{3} C O C H_{3} + C a (O H)_{2} \to 2 C H C l_{3} + (C H_{3} C O O)_{2} C a$
(iii) Formaldehyde reacts with Fehling Solution to form anion of formic acid.
$H C H O + 2 C u^{2 +} + 5 O H^{-} Δ - \to H C O O^{-} + + C u_{2} O ↓ + 3 H_{2} O$

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