What happens when:
(i) $S O_{2}$ gas is passed through an aqueous solution of $F e^{+ 3}$ salt?
(ii) $X e F_{4}$ reacts with $S b F_{5}$ ?

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Solution

(i) When $S O_{2}$ gas is passed through an aqueous solution of $F e^{+ 3}$ salt, it reduces ferric ions to ferrous ions.
$S O_{2} + 2 F e C l_{3} + 2 H_{2} O \to H_{2} S O_{4} + 2 H C l + 2 F e C l_{2}$
(ii) $X e F_{4}$ reacts with $S b F_{5}$ to form an adduct $[X e F_{3}]^{+} [S b F_{6}]^{-}$ .
$X e F_{4}$ acts as fluorine donor.
$X e F_{4} + S b F_{5} \to [X e F_{3}]^{+} [S b F_{6}]^{-}$
$X e F_{4}$ acts as a lewis base and $S b F_{5}$ acts as lewis acid.

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