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Ion Electron Method

What happens ...

Question

What happens when-
Sulphur is boiled with caustic soda solution.

4 S + 6 N a O H ⟶ {N a}_{2} S_{2} O_{3} + 2 {N a}_{5} S + 3 H_{2} O E x c e s s s u l p h u r - ---------- \to {N a}_{4} S_{5}

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4 S + 6 N a O H ⟶ {N a}_{2} S_{2} O_{4} + 2 {N a}_{2} S + 3 H_{2} O E x c e s s s u l p h u r - ---------- \to {N a}_{3} S_{5}

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4 S + 6 N a O H ⟶ {N a}_{3} S_{2} O_{6} + 2 {N a}_{2} S + 3 H_{2} O E x c e s s s u l p h u r - ---------- \to {N a}_{2} S_{5}

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4 S + 6 N a O H ⟶ {N a}_{2} S_{2} O_{3} + 2 {N a}_{2} S + 3 H_{2} O E x c e s s s u l p h u r - ---------- \to {N a}_{2} S_{5}

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Solution

The correct option is D $4 S + 6 N a O H ⟶ {N a}_{2} S_{2} O_{3} + 2 {N a}_{2} S + 3 H_{2} O E x c e s s s u l p h u r - ---------- \to {N a}_{2} S_{5}$
Sulphur is boiled with caustic soda solution
$4 S + 6 N a O H ⟶ {N a}_{2} S_{2} O_{3} + 2 {N a}_{2} S + 3 H_{2} O E x c e s s s u l p h u r - ---------- \to {N a}_{2} S_{5}$

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